Re: RI3PJM = IR2OO1 + IR2OO2 kako?
To se odnosi na polaganje OO1 i OO2 iz delova (svaki po 2 kolokvijuma). A oni mogu da se polazu i odjednom, tj. jednom izdadjem na integralni OO1 i jednom na integralni OO2. To je kao parcijalni PJM. E to me zanima.
Mada, mozda je bolje i integralno polagati ceo PJM, ako je i dalje po starom - odradis jedan zadatak u C++ i 'samo' ga prevedes u Java-u.
P0Z!
On Sat, 06 Aug 2005 12:44:37 +0200, Veljko Zrnic <zrnicv@EUnet.yu> wrote:
--
## Marko Stankovic ## Registered Linux User #361318 [counter.li.org]
Using Opera's revolutionary e-mail client: http://www.opera.com/m2/
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The act of removing Windows from your computer in disgust, usually followed
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Mada, mozda je bolje i integralno polagati ceo PJM, ako je i dalje po starom - odradis jedan zadatak u C++ i 'samo' ga prevedes u Java-u.
P0Z!
On Sat, 06 Aug 2005 12:44:37 +0200, Veljko Zrnic <zrnicv@EUnet.yu> wrote:
Koliko sam ja shvatio, iz delova (OO1 + OO2) mozes da polazes samo kao
preko kolokvijuma (parcijalno). Tj. u januaru prijavis kolokvijum, pa
onda u junu prijavis ispit (PJM) i izadjes na OO2... u svim drugih
slucajevima moras da izadjes na sve odjednom. Naravno, sasvim je
moguce da gresim, tako da najbolje pitaj Krausa...
--
## Marko Stankovic ## Registered Linux User #361318 [counter.li.org]
Using Opera's revolutionary e-mail client: http://www.opera.com/m2/
Defenestration n. (formal or joc.):
The act of removing Windows from your computer in disgust, usually followed
by the installation of Linux or some other Unix-like operating system.
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