Re: jos jedno pitanje...
Ispravljeno je.
n treba da bude na poziciji 2.
> Memorija.doc
>
> Zadatak 1:
>
> Zasto:
>
> b ProcStack 1
> b.x Heap Value(fp+1) + 0
> b.y Heap Value(fp+1) + 1
> n ProcStack 3
>
> A ne:
>
> b ProcStack 1
> b.x Heap Value(fp+1) + 0
> b.y Heap Value(fp+1) + 1
> n ProcStack 2
>
> pozdrav
>
> Veljko
>
> -----------------------------------------------------------------
> unsubscribe:
> minimalist@titan.etf.bg.ac.yu?subject=unsubscribe%20ri4pp
> -----------------------------------------------------------------
>
>
n treba da bude na poziciji 2.
> Memorija.doc
>
> Zadatak 1:
>
> Zasto:
>
> b ProcStack 1
> b.x Heap Value(fp+1) + 0
> b.y Heap Value(fp+1) + 1
> n ProcStack 3
>
> A ne:
>
> b ProcStack 1
> b.x Heap Value(fp+1) + 0
> b.y Heap Value(fp+1) + 1
> n ProcStack 2
>
> pozdrav
>
> Veljko
>
> -----------------------------------------------------------------
> unsubscribe:
> minimalist@titan.etf.bg.ac.yu?subject=unsubscribe%20ri4pp
> -----------------------------------------------------------------
>
>
- References:
- jos jedno pitanje...
- From: Veljko Pejovic <veljkoveljko@gmail.com>
- jos jedno pitanje...
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